I am trying to understand following signal trace picture that is shown on the wiki page of 1553 Bus. The Bus has balanced differential pair wires.
As the 1553 bus has differential signals on the twisted pair of wires it means that the physical arrangement of the oscilloscope probe was that the probe SIGNAL and GND pins would be connected on the differential wire-pair. As there is no 'ground' wire in the 1553 bus so the oscilloscope probe GND will not be connected to any 'ground' potential but one of the two differential wires will act as the reference potential point (ground) for the oscilloscope input signal.
In the picture I can see 3 voltage levels, Low, Mid and High. My understanding is that when the Bus is quiet then both lines are at 0 volts w.r.t their signal ground so their difference will also be 0 volts. It looks like this is the 'Mid' signal level case.
I could not understand how the Logic '0' and '1' is translated as 'Low and 'High' in the above signal trace on the oscilloscope? If I want to draw the individual signals on the differential lines w.r.t. to the signal ground then what would be those 2 signal traces that produces the trace as shown in the above picture?