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Draw the circuit diagram for DC and determine the component value. The transistor must be biased with :

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This is my attempt to solve this

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The picture bellow is the way I drew the DC circuit diagram

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I would really appreciate if I could get some feedback regarding and some help on how to find R2

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  • \$\begingroup\$ "The transistor", would that be Q1 or Q2? \$\endgroup\$
    – winny
    Jan 30 '20 at 13:18
  • \$\begingroup\$ @winny , in this case it would be both because R2 is connected to both of them \$\endgroup\$
    – E199504
    Jan 30 '20 at 13:22
  • \$\begingroup\$ Please name the components exactly as shown in the original question, and it's not clear what those parameters are given for which transistor. For example, probably \$U{CE-A}\$ indicates the voltage across C and E terminals of the transistor A (QA or something). Also, it seems that you have created the schematics with Circuit Lab. You don't have to put a screenshot, instead you can directly put the schematics inside the question. It allows you to modify the circuit. \$\endgroup\$ Jan 30 '20 at 13:28
  • \$\begingroup\$ @Rohat Kılıç , Uce is across C and E terminals for both transistors. I tried but I need a paid membership to be able to do that \$\endgroup\$
    – E199504
    Jan 30 '20 at 13:30
  • \$\begingroup\$ Please do not refer to two transistors as "the transistor". Please use component designators and refer to them. \$\endgroup\$
    – winny
    Jan 30 '20 at 13:41
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Some parts of your question are a bit fuzzy. Improve that next time.

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  • \$\begingroup\$ thank you. How come Re is equal to 10kohm ?. Shouldn't Re= 7.3v/4mA ? \$\endgroup\$
    – E199504
    Jan 30 '20 at 16:23
  • \$\begingroup\$ that's a fuzzy part in 1st pix \$\endgroup\$ Jan 30 '20 at 17:05
  • \$\begingroup\$ what do you mean by fuzzy part ? I can upload a better quality picture of the circuit.. Shouldn't Re= 7.3v/4mA ? \$\endgroup\$
    – E199504
    Jan 30 '20 at 17:17
  • \$\begingroup\$ There are 2 caps and Re given as 10k, it doesn't make sense to have more current =4mA in Q1 yet Re was given if I read it OK ...fuzzy \$\endgroup\$ Jan 30 '20 at 17:45
  • \$\begingroup\$ I see it is RL not Re so yes Re=1.8k=7.3V/4mA \$\endgroup\$ Jan 30 '20 at 17:54

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