I already know the answer of question 1, 2 and 3.
1) 448 ohm
2) 1.6 V
3) 0.13 V
About the question 4, why 6V/300 = 0.02A = 20mA is wrong? Can I use current divider like 0.01339 * (3.3 * 10^3 / (300 + 3.3 * 10^3))? But, the answer still wrong.
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Sign up to join this communityI already know the answer of question 1, 2 and 3.
1) 448 ohm
2) 1.6 V
3) 0.13 V
About the question 4, why 6V/300 = 0.02A = 20mA is wrong? Can I use current divider like 0.01339 * (3.3 * 10^3 / (300 + 3.3 * 10^3))? But, the answer still wrong.
By superposition, the current thru R=300 splits into two paths that results in the sum for the answer in 4).
R1 = 300+100+100 = 500
R2 = 300+3k+1k+100 = 4k4
I(R=300)=6/500 +6/4k4