# For the network shown in the figure, draw the corresponding Thévenin equivalent circuit and establish its parameters VT and RT I can't find any examples online similar to this format, please help! Attempt: RT = (2*5)/(2+5) = 10/7 = 1.429 k-ohms VT = 8V + 8V = 16 V Do you ignore the center resistor and just add the voltages together?

• @brhans here was my attempt: VT = 8V + 8V = 16V; RT = (2*5)/(2 + 5) = 10/7 = 1.429 k-ohms – jorkz Feb 4 at 20:19
• refer to your course material and speak to your instructor .... you may have missed something in your previous lessons – jsotola Feb 4 at 20:21
• Your attempt is incorrect for VT. Here's a hint on how to find that: If you took a multimeter and measured the voltage between A and B, what would your multimeter tell you? – KingDuken Feb 4 at 20:44
• @KingDuken would it be 8 V as the other 8 V is solely channeled to the two 2 k-ohm resistors? – jorkz Feb 4 at 20:52
• Just look at the top half for a moment...what is 'a' in relation to the upper voltage source? Hopefully you can figure it out from there. – evildemonic Feb 4 at 21:12