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I can't find any examples online similar to this format, please help! Attempt: RT = (2*5)/(2+5) = 10/7 = 1.429 k-ohms VT = 8V + 8V = 16 V Do you ignore the center resistor and just add the voltages together?

  • \$\begingroup\$ @brhans here was my attempt: VT = 8V + 8V = 16V; RT = (2*5)/(2 + 5) = 10/7 = 1.429 k-ohms \$\endgroup\$
    – jorkz
    Commented Feb 4, 2020 at 20:19
  • \$\begingroup\$ refer to your course material and speak to your instructor .... you may have missed something in your previous lessons \$\endgroup\$
    – jsotola
    Commented Feb 4, 2020 at 20:21
  • \$\begingroup\$ Your attempt is incorrect for VT. Here's a hint on how to find that: If you took a multimeter and measured the voltage between A and B, what would your multimeter tell you? \$\endgroup\$
    – user103380
    Commented Feb 4, 2020 at 20:44
  • \$\begingroup\$ @KingDuken would it be 8 V as the other 8 V is solely channeled to the two 2 k-ohm resistors? \$\endgroup\$
    – jorkz
    Commented Feb 4, 2020 at 20:52
  • 1
    \$\begingroup\$ Just look at the top half for a moment...what is 'a' in relation to the upper voltage source? Hopefully you can figure it out from there. \$\endgroup\$ Commented Feb 4, 2020 at 21:12

1 Answer 1


When a and b are open, the two 2K resistors in the upper circuit form a voltage divider. When a and b are short, the short current flowing back through 5K resistor. Does this help?


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