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A DC device operates with three industrial AA batteries meaning 1.5V times three = 4.5V. Besides that I only know that the approximate operating time is is 4 hours.

Is that possible to estimate the load in terms of resistance roughly?

Battery info: Three AA Type 1.5V 1500 mAH in series making 4.5V in total.

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  • \$\begingroup\$ How do you know the batteries are in series and not parallel? \$\endgroup\$ – Ron Beyer Feb 7 at 14:24
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3 × 1.5 V, 900 mAh gives 4.5 V, 900 mAh.

Run time = 4 hours so \$ I = \frac {900\ \text {mAh}}{4 \ \text h} = 225 \ \text {mA} \$.

The effective load resistance is given by \$ R = \frac {V}{I} = \frac {4.5}{225} \$ which will be left as an exercise for the reader.

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  • \$\begingroup\$ I found more info on batteries : AA Type 1.5V 1500mAH times 3 = 4.5V in total \$\endgroup\$ – user1245 Feb 7 at 14:29
  • \$\begingroup\$ Can you work it out yourself now? \$\endgroup\$ – Transistor Feb 7 at 14:30
  • \$\begingroup\$ Yes I can thanks! \$\endgroup\$ – user1245 Feb 7 at 14:31

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