# Voltage drop across junctions in a bjt transistor

Above is a npn transistor with a battery connected across emitter and collector.

My textbook and all online resources seem to say this: No current flows in above circuit because the emitter-base junction is not forward biased. The current will flow when another battery is connected across emitter-base junction.

But doesn't the existing battery across emitter-collector already make the emitter-base diode forward biased? Where would all the voltage of that battery appear?

Observations:
If emitter-base junction is not forward biased, then both the junctions will have large but same resistance. This means half the battery voltage appears across each junction. This makes the emitter-base junction forward biased.

Where is my error?

There will always be a leakage current from collector to base and emitter ($$\I_{CEO}\$$). This might be in the region of 100 nA and, at that current, the base emitter junction appears to be forward biased as if that 100 nA were flowing through a diode. There might be about 0.2 volts dropped across base emitter in this scenario.