I volunteer at a club to teach teens Arduino and basic electronics: LEDs, resistors, voltage, current, etc. I also describe what they do:

Batteries, chargers and other power supplies:

  • These supply plenty of electrons to make the circuits work.
  • The higher the number of electrons it generates at once, the higher the voltage it supplies. Too many can burn out a device not expecting it: explosion!
  • The higher the number of electrons it can supply per time period, the higher its rated current. If the circuit demands more than the supply can actually deliver, the supply either overheats and explodes, or gives up by stopping producing electrons (lowers the voltage).

LEDs get "excited" when electrons pass through them, and they glow when there are enough:

  • It takes a certain number of electrons to get things started - but once that happens LEDs will quickly let so many through that they overheat and explode!

Resistors don't let all the electrons through at once - the higher their value, the fewer electrons they let pass:

  • They make up the difference in heat;
  • If there are lots of electrons (high voltage) but little resistance (value), there will be a high number of electrons per time period (current). The resistor will get hot, and maybe overheat and explode!
  • Putting a resistor inline with an LED will limit the number of electrons per time period (current) passing through the LED, stopping the LED from receiving too many at once, and preventing overheating and explosions.

(I've found that emphasising explosions keeps them interested and amused: see LEDs no longer bang - or whimper!)

But when I get to capacitors, I've never found a convincing explanation - and the Wikipedia Capacitor "Hydraulic analogy" just makes me cringe: it hand-waves a lot of the effects.

So I describe it thusly:

A capacitor is two large plates of thin metal, separated by a very thin layer of "stuff" (called a dielectric) that doesn't let electrons through. They can be manufactured by rolling that triple "sandwich" into a tight cylinder or other compact form (with suitable insulation); they still work the same. The larger the plates involved or the closer the two plates are to each other, the higher rating the capacitor has. Of course, the dielectric has limitations: for example, too high a voltage between the plates will burn straight through the dielectric. This will "short" the two plates together into a very low value resistance: explosion!

If you put a capacitor across a battery, interesting things happen. Think about when the capacitor was manufactured: both plates of metal have (about) the same number of electrons in each of them. When you put the combination across a battery, then one side gets extra electrons supplied. Those electrons can't pass through the thin dielectric; but since they're so close, they actually electrically "repel" the other plate's electrons, forcing them out the other side of the capacitor. As more electrons go in one side, more are repelled and forced out the other. Note none are passing through the capacitor: the ones leaving just don't want to be there anymore!

However that effect is limited. Pretty soon the second side starts to run out of electrons to repel - the ones still there are bound too strongly to their atoms to be so easily pushed out - and the 'apparent' current leaving the capacitor dwindles to nothing. The capacitor is considered "saturated", or fully charged. The electrons in the over-supply side still kind of want to stick around: they're still being pushed by the incoming voltage, and are even attracted to the positive charge of the opposite side that they helped to create! If the voltage reduces though, then some electrons will come back out: the capacitor is discharging.

If you disconnect the capacitor from the battery completely, each side still holds an unequal number of electrons. In fact, if you were to touch both ends you'd provide a path that would allow all of the excess electrons on one side to immediately make up the deficiency of electrons on the other - and there'd be nothing other than your inate resistance to limit the passage of those electrons! In other words, if the resistance was low enough, there'd be an explosion - in YOU! (Ouch!) Note that since there's no passage of electrons through the capacitor - they're all there just waiting to move - it can discharge extraordinarily quickly.

So, given that a capacitor can store excess electrons but also release them quickly, that means that they're good at "smoothing" peaks and troughs in either voltage or current - until it saturates or runs out of charge.

So, I fully agree that the above does not follow the standard description of capacitors. But that's not the question - is the above wrong?

  • 7
    \$\begingroup\$ Your first section is missing the concept of current. It's not the "number of electrons" that matters but the rate of flow (current is charge per unit time). I would also caution too much emphasis on "electrons" as it causes great confusion with conventional current flow. Remember that in some circumstances that positive ions can flow too. \$\endgroup\$
    – Transistor
    Feb 27, 2020 at 10:57
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    \$\begingroup\$ I disagree with the first sentence used to describe capacitors. The use of the words large and thin presumes all capacitors are intentionally made like this. I also don't like rolling that triple "sandwich" into a tight cylinder because you fail to see that doing so would short plates out. I'm stopping now. \$\endgroup\$
    – Andy aka
    Feb 27, 2020 at 11:00
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    \$\begingroup\$ Voltage isn't the number of electrons at once. Batteries/chargers/etc also don't generate electrons, they pull electrons (or push, if you prefer) the way that pedals pull a bicycle chain. \$\endgroup\$
    – user253751
    Feb 27, 2020 at 11:22
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    \$\begingroup\$ In the first batteries and chargers section, I strongly disagree with 'higher number of electrons at once, the higher the voltage'. The hydraulic analogy is excellent here, potential energy is voltage is height. Charge is volume of water, current is rate of flow, height difference is potential difference, height needs a reference. Why use 'electrons' when 'charge' is a similar concept, and less likely to lead to the need to unteach stuff later on. \$\endgroup\$
    – Neil_UK
    Feb 27, 2020 at 11:39
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    \$\begingroup\$ Your explanations for what causes higher voltage, how resistors work, and how LEDs work are very mistaken. You need to learn about the concept of energy in electronic devices and circuits. Please don't give these explanations to young people. \$\endgroup\$ Feb 27, 2020 at 12:41

1 Answer 1


I suggest you start using water analogies for describing the working principles of electric components. In my experience, water analogies are best for understanding electricity. Here's a very good analogy for DC electric circuit with capacitor.

enter image description here Source: https://www.slideshare.net/avikdhupar/robotics-workshop-ppt

enter image description here Souce: https://ppt-online.org/22777

  • \$\begingroup\$ Thanks for that (although I'm trying hard to ignore the "membranne" typo). The idea of the membrane "bursting" with too much pressure is irresistable! What I've found though is that the water analogy fails quite quickly when trying to describe inductance - the third concept after resistance and capacitance. Talking about how inductors work using electrons works far better than the whole "water" thing - unless you've got a better description? \$\endgroup\$ Feb 27, 2020 at 12:11
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    \$\begingroup\$ @JohnBurger, check out the link for Wikipedia. All electric phenomena can be described with water. Passive heavy turbine perfectly describes the inductor. For your own good sake and for the benefit of your student, I suggest you build real models for all water analogies. \$\endgroup\$
    – Marino
    Feb 27, 2020 at 12:24
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    \$\begingroup\$ Google water hammer. There's your inductance right there. \$\endgroup\$
    – Dampmaskin
    Feb 27, 2020 at 13:13
  • \$\begingroup\$ @JohnBurger: For inductance in the water analogy, you use a section of thin walled pipe with a very narrow open path - like you cut out a section of pipe and replaced it with a long, skinny balloon. At first, no water flows. The balloon expands, water flows. When you shut off the water supply, the balloon squeezes shut again and forces the water out. That does a fair job of mimicing current flow in an inductor. \$\endgroup\$
    – JRE
    Feb 27, 2020 at 13:17
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    \$\begingroup\$ @JohnBurger An inductor should be modeled as a water turbine coupled to a heavy flywheel. It takes high pressure to cause the rate of flow of water to change quickly (v = L di/dt). Energy is stored in the rotation of the flywheel. Unlike the expanding balloon model, this model also has two terminals and models current flow properly in either direction through the inductor. \$\endgroup\$ Feb 27, 2020 at 18:07

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