0
\$\begingroup\$

enter image description here The diagram above is what was given to me. I have to make:

Vce = 1V Ib = 30uA

I have two variable components, namely, Vcc (Voltage source from the collector), and Rin(supposed to be a pentiometer in practical applications). I was tasked to find Ic, but I'm having trouble because I'm only going with a trial and error approach to the circuit so that I can achieve the requirements above with the Vce and Ib, but I can't seem to find the correct values.

\$\endgroup\$
  • \$\begingroup\$ Try to read this electronics.stackexchange.com/questions/471906/… \$\endgroup\$ – G36 Mar 1 at 7:06
  • \$\begingroup\$ You have no information on \$\beta\$ and no information about \$V_\text{BE}\$. Also, you only have one ground reference, the emitter itself. The other voltage supplies are in some way floating with respect to ground. In that case, \$V_\text{EE}\$ will simply circulate a current through \$R_\text{IN}\$, but otherwise has no impact on the circuit. So \$R_\text{IN}\$ is irrelevant. \$\endgroup\$ – jonk Mar 1 at 8:49
  • \$\begingroup\$ That's a horrible way to draw a schematic. If you did it properly, you'd see that you're short-circuiting the base with the collector (thus the nodes Vbe and Vce are the same, causing node "aliasing") and that the sources have no reference to ground (which I suspect you're trying to achieve). \$\endgroup\$ – a concerned citizen Mar 1 at 20:25

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.