# I can't reach the correct current with a BJT in LTSpice

The diagram above is what was given to me. I have to make:

Vce = 1V Ib = 30uA

I have two variable components, namely, Vcc (Voltage source from the collector), and Rin(supposed to be a pentiometer in practical applications). I was tasked to find Ic, but I'm having trouble because I'm only going with a trial and error approach to the circuit so that I can achieve the requirements above with the Vce and Ib, but I can't seem to find the correct values.

• Try to read this electronics.stackexchange.com/questions/471906/… – G36 Mar 1 at 7:06
• You have no information on $\beta$ and no information about $V_\text{BE}$. Also, you only have one ground reference, the emitter itself. The other voltage supplies are in some way floating with respect to ground. In that case, $V_\text{EE}$ will simply circulate a current through $R_\text{IN}$, but otherwise has no impact on the circuit. So $R_\text{IN}$ is irrelevant. – jonk Mar 1 at 8:49
• That's a horrible way to draw a schematic. If you did it properly, you'd see that you're short-circuiting the base with the collector (thus the nodes Vbe and Vce are the same, causing node "aliasing") and that the sources have no reference to ground (which I suspect you're trying to achieve). – a concerned citizen Mar 1 at 20:25