# Heat dissipation from PCB

I have a PCB with several power ICs. The PCB is connected to an aluminium plate as a heatsink on the back of the PCB.

How can I measure how much heat dissipates from the top of the PCB to the air and how much heat is conducted by the heatsink? I want to know it for the entire PCB and not only for the individual components.

• The amount of heat produced is electrical power in minus electrical power out so, if your circuit doesn't have any down stream electrical connections of notable power consumption, then the total heat produced is the electrical power in measured in watts. I realize that this doesn't answer your specific question but it might help. Commented Mar 2, 2020 at 13:39
• The temperature across a PCB made of typical FR-4 (there are lots of variants) can vary significantly as the thermal conductivity is quite low; this can be controlled (a bit) by using planes but for a power board the temperature across the PCB will typically vary quite widely. Commented Mar 2, 2020 at 14:19
• Essentially you can't. As Andy says you can measure power in... but you can also measure its temperature. So one approach is to measure its temperature while varying input power until you have a good picture of the relationship between them. If you can't control the power directly, bolt one of those metal-cased resistors to the heatsink and dissipate power in that.
– user16324
Commented Mar 2, 2020 at 14:46
• Thinking out loud here...What if you were to mount the PCB into the wall of a small insulated container, like a styrofoam cooler, with the aluminum heatsink on the outside and the board on the inside of the container? Close up the container and monitor the inside temperature while the board is being powered/used. The temperature rise should be proportional to the heat being dissipated by the PCB into the container. Knowing the volume and specific heat of the inside of the container (air), you should be able to calculate the heat being put into the chamber. Sort of a poor man's calorimeter. Commented Mar 2, 2020 at 17:02
• Continuing @SteveSh's approach: now that you monitored the temperature rise in the given chamber / container, you can put a power resistor in the same container and power it from a direct current (DC) source. Adjust the power to get the same temperature rise profile ( should be following a function like A( 1 - e^(- t/Tau)), where A and Tau are parameters, e is the Euler number and t is time. The power you have to burn in the known resistor P = V^2/R (with V being the DC voltage across it and R the resistance of the resistor) gives you the power that your original PCB dissipates. Commented Mar 2, 2020 at 22:57