I'm designing an interface board to connect a MIPI DSI LCD screen to an RPi. The screen is a KWH070KQ40-C08
(link to pdf), but the datasheet isn't quite clear and I don't get an answer from the company. I tried googling, but found no topic talking about interfacing MIPI DSI screens.
These are the pins with their recommended voltages. The datasheet only talks about current draw on the LED+/LED- pin (which is around 180mA
).
- LED+: 10V (Anode LED blacklight)
- LED-: 0V (Kathode LED blacklight)
- LCD_VGH: 18V (Gate ON Voltage)
- LCD_VGL: -6V (Gate OFF Voltage)
- AVDD: 9.6V (9.4V - 9.8V) (Power for analog circuit)
- VDD: 3.3V (Power for digital circuit (1.8V))
- VCOM: 3.15V (2.85V - 3.45V) (Common Voltage)
The board will be powered by a 5V
USB connection and has a 3.3V
voltage regulator. (not on schematic)
For making the 10V
(LED+
), I plan on using a DC-DC switching converter (MIC2288), which may or may not be an overkill. Can I connect LED-
with the ground or do I use a 0R
resister inbetween?
For VCOM
and AVDD
I was thinking on using respectively +3.3V
and +10V
and drop the voltage with a Schottky diode or voltage divider with buffer. But since I don't know the current draw I'm not sure what to choose.
Same goes for LCD_VGH
and LCD_VGL
, I could use a second MIC2288
, make 24V
and shift it down somehow by 6V
. Or use 2 voltage converters for making -6V
and +18V
.
Besides the power pins, we have the 4 datapairs and clockpair. These I will connect directly. (not on schematic)
Lastly, the 4 signal
lines. UPDN
, SHLR
, STBYB
and LRSTB
, as there is no further information about these pins, I made room for a pullup and pulldown resistor so I test which one it is. (not on schematic)
VDD
should be3.3V
but then they add1.8V
in brackets. I think they regulate the voltage themself to1.8V
, -as I don't see otherVDD
pins mentionned in the pinout. \$\endgroup\$UPDN
,SHLR
are and how to use the reset pins. I'll have to test to see if they're active low or high though. \$\endgroup\$