0
\$\begingroup\$

I have a USB C port on my computer and a USB C male-to-male cable, as well as USB C female and USB A 3.0 female breakout boards.

I have connected my computer to the breakout via USB C cable and wired the USB C breakout to the USB A breakout. So, I can connect devices to the USB A breakout to connect to my computer. The connections I used are below.

My problem is the CC1 and CC2 logic. I read about the pullup and pulldown networks needed for UFPs and DFPs for USB C. Some sources: (1), (2). So, I connected CC1 to a 5.1k resistor and connected that to ground. I did the same for CC2. This works when I plug in a USB 2.0 mouse (it uses D+ and D-) but this does not work for my USB 3.0 drive (even when I flip the cable).

USB A USB C
1 -> A4,A9,B4,B9
2 -> A7
3 -> A6
4,7 -> A1,A12,B1,B12
5 -> B10
6 -> B11
8 -> A3
9 -> A2

Do I need a different resistor pullup/pulldown network in order for my design to work with USB 3.0?

\$\endgroup\$
1
\$\begingroup\$

If your A-to-C breakout does not have sufficient impedance control and other signal quality means to support Super-Speed signals (and even HS signals), your USB 3 drive won't work. And usually all commonly available C-C and A-C breakouts don't meet the necessary signal integrity requirements by long-long mile. Different CC logic won't fix this.

| improve this answer | |
\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.