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I was reading some posts about how light can damage a camera by heating it up its internal components? Link: Can camera sensors be damaged by light?

If I shine a 150-lumen flashlight at a monitor or webcam constantly for 5 minutes will it result in damage? A simple explanation of why or why not would be very helpful. Will it cause overheating?

How does the magnifying glass effect apply to this

Thank you for helping me understand.

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  • \$\begingroup\$ What distance? optical to electrical power conversion is a risk. What is the distance? The light does not transmit heat so not much unless the surface is hot, \$\endgroup\$ – Tony Stewart Sunnyskyguy EE75 Mar 27 at 1:08
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If I shine a 150-lumen flashlight at a monitor or webcam constantly for 5 minutes will it result in damage?

150 lumen is a few hundred milliwatts, and it will be distributed over a wide area, so heating will be negligible. At that power level you would need a very small spot to do any real heating.

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  • \$\begingroup\$ Would you say even if the flashlight was making surface to surface contact (Very Close) while on it would still not cause damage to a monitor or webcam? Thanks \$\endgroup\$ – BunLad Mar 27 at 1:09
  • \$\begingroup\$ @BunLad I think you would need to make that flash light a couple orders of magnitude brighter before there would be a problem. \$\endgroup\$ – user1850479 Mar 27 at 2:36
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Most likely your fault is ignoring the O-to-E voltage convertion in each photovoltaic cell with -5V being a typical max.

Whereas an LCD or LED backlight does not such a low sensitivity to high impedance damage.

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  • \$\begingroup\$ In my scenario would it cause damage to the monitor or webcam, distance is about one inch \$\endgroup\$ – BunLad Mar 27 at 1:25
  • \$\begingroup\$ Probably...is my guess... \$\endgroup\$ – Tony Stewart Sunnyskyguy EE75 Mar 27 at 6:42
  • \$\begingroup\$ @TonyStewartSunnyskyguyEE75 You may well be right, but can you explain in more detail why you have come to this conclusion. Quick scribblings do suggest a surface brightness several times full noon sunlight (~= 100 klux) [based on several assumptions] but energy density is in the order of 600W/m^2 (assuming a say 400 mm^2 effective source area). \$\endgroup\$ – Russell McMahon Mar 27 at 9:06
  • \$\begingroup\$ When I get time, I'll get the proof and example how a "smart" Nikon will defocus automatically. Does his? @RussellMcMahon Does he feel luckY? You can get filters to block IR,UV. So if using a smart Nikon and say you are watching a cloudy sunset then it goes bright instantly before setting. This defocus is self-protection (...) Some countries have reduced to 2x suspect viral rates in 1 day globe average is 6 days, China 40 days ....I digress...Yet most digital cams do not have this. protection measured by cell voltage. \$\endgroup\$ – Tony Stewart Sunnyskyguy EE75 Mar 27 at 17:48

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