I am making a negative edge triggered d-flip flop using the schematic attached, I have already put in the reset (attached) but the reset needs me to have a 4 input nor gate, which isn't provided in the program I'm using. What I am asking is how I would turn this 3 input nor gate into a 4 input nor gate. I was thinking something like what I drew on the side of the diagram, but I don't know if it would work.

enter image description here

  • \$\begingroup\$ Rotate your picture dude. \$\endgroup\$
    – Andy aka
    Mar 28 '20 at 17:16
  • \$\begingroup\$ ill try but its a scan \$\endgroup\$
    – liaiwen
    Mar 28 '20 at 17:27
  • \$\begingroup\$ the image size is over 2MB when i try \$\endgroup\$
    – liaiwen
    Mar 28 '20 at 17:47
  • 1
    \$\begingroup\$ No it wasn't. You need to try harder. \$\endgroup\$
    – Andy aka
    Mar 28 '20 at 18:29

No that doesn't work:

\$(A+B + (C+D)')' \ne (A+B+C+D)'\$.

Try this using three 3 input NOR gates:

\$((A+B+C)'' + D+0)' = (A+B+C+D)'\$ enter image description here

  • \$\begingroup\$ so how would I go about doing it then? \$\endgroup\$
    – liaiwen
    Mar 28 '20 at 18:00
  • \$\begingroup\$ @liaiwen How about a 2-input OR? \$\endgroup\$ Mar 28 '20 at 18:01
  • \$\begingroup\$ could you draw that please? \$\endgroup\$
    – liaiwen
    Mar 28 '20 at 18:16
  • \$\begingroup\$ @liaiwen updated with the drawing \$\endgroup\$
    – across
    Mar 28 '20 at 18:21
  • \$\begingroup\$ isnt the 2nd nor gate just an inverter? \$\endgroup\$
    – liaiwen
    Mar 28 '20 at 18:59

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