# Is the resultant field of a three phase wound stator always two pole?

Suppose I have a stator, where I've allocated one coil for each phase and I supply a balanced three-phase supply. So the fields, $$B_r = B_{max}\cos(\theta_{mech})\cos(\theta_{elec}) \\ B_y = B_{max}\cos(\theta_{mech}-120)\cos(\theta_{elec}-120) \\ B_b = B_{max}\cos(\theta_{mech}-240)\cos(\theta_{elec}-240)$$ whose sum ultimately gives, $$B_{res} = \dfrac{3}{2}B_{max}\,cos(\theta_{elec}-\theta_{mech}) = \dfrac{3}{2}B_{max}\,cos(\omega_{elec}t-\theta_{mech})$$ which is a rotating magnetic field with a frequency of $$\\omega_{elec}\$$.

Now, what happens if I've allocated 2 coils for each phase such that each coil crates 4 poles, what will be the resultant field? Will it have four poles rotating? Maybe like this\https://imgur.com/a/hWxnfOm ?

Or does the first set of RYB produce a rotating field $$\B_{res1}\$$ and second set of RYB produce $$\B_{res2}\$$ (I've no clue for what's the phase-difference between these two resultants)and the final resultant a sun of these two will be two-pole?

• I think you're describing a four-pole motor? These are very common, and yes, the field (and rotor) rotate at half the speed of a two pole. Apr 3 '20 at 6:28 