we add another diode in the circuit. Shown in the picture below:
The questions are:
- Before adding the second the diode the voltage at the input and output where smaller, why was that?
- Why positive side of the capacitor C3 was connected to ground?
For the first question the answer I thought was that the negative excursion of the output signal forward bias the diode causing the capacitor to increase the drain-source resistance if the JFET and reduce the gain.
For the second question the answer I thought was that the output signal forward-bias D1 causing C3 to charge to a negative voltage, thats why the negative side of the capacitor should be connected to the circuit and the positive side to the ground.
I am not sure if these answers are correct. Can someone help me with this?