# Logic network with NAND gates [closed]

I did a logic network with only NAND gates to function below: and my logic newtork Is it correct?

• Try marking each in-between output with the logical output to see if you have made an error i.e. break the problem down to smaller units. I can see an error but unless you start to analyse in sections you won't see that error. Apr 17, 2020 at 8:53
• Thank you for your answer. I think my problem is with x2 output and I'm not sure about this one inverter, I think I have to delete it and change also for nand. It will be ok? Apr 17, 2020 at 9:04
• Did you not understand my 1st comment and advice? Apr 17, 2020 at 10:51
• You need to show a bit more effort here. Take the Boolean equation and simplify it. From there it will be easier to spot any mistakes by doing the steps Andy suggests.
– MCG
Apr 17, 2020 at 11:26
• Unfortunately this function has been simplified. I can use only De Morgan laws to solve this. I've split this function for small steps and I did new circuit, I've uploaded it in Update. Apr 17, 2020 at 16:04

Your circuit simplifies to the equation Y = ~(~X1*X2) While your equation seems to simplify to Y = ~(X1*X2*X3)

How I went about simplifying was to move the inversion to the Y side for the whole equation, to simplify the right hand side,

This leaves only getting a "1" when X1 = 0, X2 = 0 and the mess on the right, to get a 1 out of this immediately the second X2 can only be 0 and the second X1 can only be a 0 to have an output, meaning the only valid state for X3 is 0 to multiply to a change on the output.

• Thank you for your help. Unfortunately I can't simplify it more because I can use only De Morgan laws to solve this. Apr 17, 2020 at 16:07
• I think if we simplified the equation, it will NOT be Y = ~(X1*X2*X3), will it?
– NAND
Apr 17, 2020 at 21:57

First we should divide our problems to smaller parts.

We should begin from a symbol which has a lot of lines over it, in this case it's $$\\overline{X_1}\$$, but in the schematic there is no $$\\overline{X_1}\$$ found so it's first error.

Then we draw(track) $$\\overline{\overline{X_1}X_3}\$$, then we draw(track) $$\\overline{X_2}\$$ and so on to reach our function $$\Y\$$

Using these steps will make you analyze the problem and discover errors faster!.

I think schematic should be like that: Here is the schematic after editing it. But I think you'd better simplify the boolean equation algebraically then try to draw our schematic. If we simplify it we will get $$Y=X_1+\overline{X_2}\,\overline{X_3}$$