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I do not understand the concept of convolution. If possible could you please explain in layman terms so that I can solve this question.

What is the h(t)?

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  • \$\begingroup\$ Welcome to EE.SE. It seems that this question is part of your study. It won't help to explain it in layman's terms if you want to get a professional. It is near impossible to understand convolution without integrals. And integrals are by no way layman's terms. You need to understand integration and transformation. \$\endgroup\$
    – Ariser
    Apr 22, 2020 at 15:39

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HINT

The transfer function in the s-domain (using Laplace transform) is given by:

$$\mathcal{H}\left(\text{s}\right):=\frac{\text{v}_\text{o}\left(\text{s}\right)}{\text{v}_\text{i}\left(\text{s}\right)}=\frac{\text{R}}{\text{R}+\text{sL}}\tag1$$

Using the definition of the Laplace transform we know:

$$\text{v}_\text{i}\left(\text{s}\right)=\mathcal{L}_t\left[\text{V}_\text{i}\left(t\right)\right]_{\left(\text{s}\right)}=\int_0^\infty\text{V}_\text{i}\left(t\right)\exp\left(-\text{s}t\right)\space\text{d}t=$$ $$\int_0^1\left(\theta\left(t\right)-\theta\left(t-1\right)\right)\exp\left(-\text{s}t\right)\space\text{d}t\tag2$$

Where \$\theta\left(t\right)\$ is the Heaviside Theta function.


Besides that, an impulse response of a system is given by the output of a system when a Dirac delta function is applied to the input.

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