strong text

Can anyone please help me in understanding the output of this amplifier? According to me it is coming as (E1-E2)(1+(Rw/R)).

I am more curious about knowing wheather Rw will come in the output equation or not, and if not how will it get eliminated.

  • 1
    \$\begingroup\$ Why not use a simulator? \$\endgroup\$
    – Andy aka
    May 1, 2020 at 9:03
  • \$\begingroup\$ How do you know that is an inst. amp? Instrumentation amplifiers normally have a single gain resistor, what you have shown looks more like a difference amplifier. \$\endgroup\$
    – Voltage Spike
    May 4, 2020 at 19:01

1 Answer 1


enter image description here

The presence of the BJT should not put you off because it's just an emitter follower AND is contained within the feedback loop (just are all the internal transistors in the signal chain inside the op-amp).

According to me it is coming as (E1-E2)(1+(Rw/R)).

Using your resistor names the gain is: -

$$\dfrac{V_O}{E1 - E2} = \dfrac{R_W + R}{R}$$

That looks to be the same as your formula.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.