0
\$\begingroup\$

Every circuit diagram of a relaxation oscillator says I have to put a 100 ohm resistor between the capacitor and the voltage source like this:

schematic

simulate this circuit – Schematic created using CircuitLab

But I think it would be better to use an 1000 ohm resistor instead of a 100 ohm resistor. This would discharge the capacitor at a slower rate and give me a lower frequency.

What do you think?

schematic

simulate this circuit

\$\endgroup\$
8
  • \$\begingroup\$ What do I think? I think you should simulate it and see if your theory is correct :) \$\endgroup\$
    – user103380
    Commented May 9, 2020 at 15:43
  • \$\begingroup\$ CircuitLab is also a simulator. Try it and see what happens. \$\endgroup\$
    – JRE
    Commented May 9, 2020 at 17:13
  • \$\begingroup\$ @JRE Does it simulate for anyone? Or do they have to sign up at CircuitLab in order to gain that feature here? \$\endgroup\$
    – jonk
    Commented May 9, 2020 at 18:05
  • \$\begingroup\$ Jelly, you will need a negative dynamic resistance region for oscillation. The zener doesn't have one. A UJT or PUJT would do, though. You can look here for a more thorough discussion. \$\endgroup\$
    – jonk
    Commented May 9, 2020 at 18:09
  • 1
    \$\begingroup\$ @SpehroPefhany Thanks. And yes, it sounds like a bit of a pain. \$\endgroup\$
    – jonk
    Commented May 9, 2020 at 19:38

1 Answer 1

1
\$\begingroup\$

I presume your "Zener" K-A is actually something like the E-(B)-C pins of an NPN BJT.

Try this out in real life (I don't think this will simulate).

I think you'll find if you increase the resistor too much, the relaxation oscillator will be very relaxed indeed and will 'stick' after the first breakdown.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.