# Problem analyzing diode circuit

simulate this circuit – Schematic created using CircuitLab

I need to find the voltage at node 3 considering all the diodes ideal. I tried the Superposition theorem to find the result.

When V2 will be shorted, then node 3 voltage should be 0 volts.

When V1 will be shorted, 'D2' will be turned off and the voltage at node 3 should be:
$$$$\frac{10}{10+5}10 = 6.667 (approximately)$$$$

So, the voltage at node 3 should be 0+6.667= 6.667 volts. But the result is provided 3.3 volts (approximately).

I did a simulation too.(Diodes of simulation causes 0.27 volt drop)

So how do I solve it ?

• Superposition applies to linear circuits. Be careful - if a diode is active with one supply, but inactive with the other supply, superposition fails. Safer to use other methods. Commented May 17, 2020 at 18:50
• Oh .. I thought that superposition is applicable anywhere. Commented May 17, 2020 at 18:52
• Superposition is only applicable to LTI (linear time-invariant) circuits. Commented May 17, 2020 at 20:16