I understand the concept of the Class D amp and this circuit, but in this particular case there is one part I just don't get.
What I don't understand is how the low side of the signal should work at the power stage. In case of the high side as I understand when the MOSFET is on, the current can flow from VCC to the load. But at the low side I don't understand how could current flow through the load and the low side MOSFET.
Could you please clarify it? Thanks!
Schematic: https://easyeda.com/omerzaid/New_Project-e38fb4c8918946298058a93ec7ef210a
J1
not have its 2nd pin to ground, but to a capacitive divider, or mid-point of two sources. The caps should be large to accomodate the current requirement, and they can serve as a replacement of two sources. Of course, the connector should be explicitely marked as "live"(!). \$\endgroup\$ – a concerned citizen May 24 '20 at 16:22