1
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I need a component/circuit which will output 1 if a 1 has been input at any time in the last 1-2ms.

I could make such a circuit out of several shift registers, an oscillator and several OR gates, or I could use an MCU.

Is there a simpler (maybe analogue) alternative? I've considered:

bus -->|--+--+-- out
          |  |
          =  R
          |  |
          _  _
          -  -
                           _
>| diode    = capacitor    - GND    R resistor

but the 1V diode drop is quite big, making the circuit very sensitive to the bus being driven at less than 3V3. There may be slew issues, with the output component not recognising an edge.

Maybe a 555 can do this?

The required logic looks like:

       _                          ____   _   __
bus __| |________________________|    |_| |_|  |______________________
       _____________________      _________________________________
out __|                     |____|                                 |__

        |<----- 1-2ms ----->|                  |<----- 1-2ms ----->|
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  • 1
    \$\begingroup\$ A 555 sure, but today we have more. eg: LTC6994 (which is basically the mcu you mention, but the hard part has been done already) \$\endgroup\$
    – Jeroen3
    Commented Jun 3, 2020 at 8:22
  • 4
    \$\begingroup\$ This sounds like a job for a one-shot, i.e. a rising edge (1) triggers the one-shot to maintain its output of 1 for a duration of 2ms. Would that meet your requirement? \$\endgroup\$
    – MarkU
    Commented Jun 3, 2020 at 8:22
  • 2
    \$\begingroup\$ The ASCII art is lovely but there's a schematic button on the editor toolbar that does a better job. When finished hit the "Save and Insert" button and an image is posted in your question with an edit link. No CircuitLab account required. \$\endgroup\$
    – Transistor
    Commented Jun 3, 2020 at 8:35
  • \$\begingroup\$ @MarkU A monostable multivibrator isn't quite what's needed. en.wikipedia.org/wiki/Monostable shows the output going low, even when the input is still high. I'll add a diagram to my post. \$\endgroup\$
    – fadedbee
    Commented Jun 3, 2020 at 8:36
  • \$\begingroup\$ @Transistor I did that, and clicked "Save and Insert" but nothing happened except for a brief circular timer. I then tried the back button, which took me back to the editor but without the circuit. \$\endgroup\$
    – fadedbee
    Commented Jun 3, 2020 at 8:47

1 Answer 1

Reset to default
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You need a re-triggerable monostable and this can be made from a 555 timer. Waveform: -

enter image description here

555 circuit using a BJT to keep the timing capacitor discharged: -

enter image description here

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  • \$\begingroup\$ First time I've seen the 555 drawn with an amplifier symbol, huh! \$\endgroup\$
    – Hearth
    Commented Jun 3, 2020 at 11:31
  • \$\begingroup\$ @Hearth maybe I can find a better one? \$\endgroup\$
    – Andy aka
    Commented Jun 3, 2020 at 11:37
  • \$\begingroup\$ I don't think there's any problem with it. It's just a bit odd to see. \$\endgroup\$
    – Hearth
    Commented Jun 3, 2020 at 11:54
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    \$\begingroup\$ The regular 555 won't work at 3.3 V, will it? \$\endgroup\$
    – Transistor
    Commented Jun 3, 2020 at 12:38
  • 1
    \$\begingroup\$ TLC555 - 2 volts to 15 volts @Transistor \$\endgroup\$
    – Andy aka
    Commented Jun 3, 2020 at 12:46

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