I designed a circuit using a SMPS voltage regulator based on the tps65261rhbr triple synchronous buck converter. The circuit is rated for up to 18V. It is connected to a 12V lawnmower battery, which also starts and powers a gasoline engine that returns charge to the battery with an alternator.

The circuit has worked perfectly over many hours of testing and switching power on and off before I connected and started the engine. Immediately upon starting the engine it failed: one of the 25V 47uF tantalum capacitors (TPSD476K025R0150) feeding the SMPS exploded.

My oscilloscope has a max of 10V, so I can't see what the input voltage waveform looks like when the engine starts and runs. I tried anyway, and I see that when the engine is started the voltage briefly dips under 10V, but outside of that brief blip it is clipped to 10V so I can't tell what's happening. I assume the voltage must have exceeded 25V for the capacitor to explode.

I'm considering switching to higher voltage (50V?) aluminum polymer bulk capacitors and a high input voltage rated 12V LDO before the SMPS to protect against input voltage spikes.

Does this seem like a good approach? Should I get a better scope or build a voltage divider to see what's really happening? Does anyone have any experience with powering circuits from an engine alternator and battery in parallel that can weigh in on this power supply design?

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    \$\begingroup\$ Can't you make a "poor man's 10x probe" for your scope (just a two-resistor voltage divider)? It's not like you need good high-frequency response or well-defined input impedance for this particular purpose. \$\endgroup\$
    – TooTea
    Commented Jun 4, 2020 at 12:30
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    \$\begingroup\$ This kind of system is prone to very large voltage spikes. en.wikipedia.org/wiki/Load_dump \$\endgroup\$
    – John Doty
    Commented Jun 4, 2020 at 12:52
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    \$\begingroup\$ Until you observe exactly what the problem is that's causing the tantalum to blow: 1) Is it a short, high voltage spike? 2) Is it a lower voltage spike, but of longer duration? 3) Is is excess ripple on the voltage (that can cause high current through the tantalum and heat it up?) - You're sort of just shooting in the dark. \$\endgroup\$
    – SteveSh
    Commented Jun 4, 2020 at 19:33
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    \$\begingroup\$ There's no telling what kind of spikes occur during the starting, with a battery feeding a high-amperage starter motor which likely generates spikes as the commutator turns. \$\endgroup\$
    – Hot Licks
    Commented Jun 4, 2020 at 21:26
  • \$\begingroup\$ @TooTea I used a voltage divider on my scope today and started/stopped the engine several times. I never witnessed the voltage go above 17-18V. I set a voltage trigger on the scope and tripped it twice at 18V, but never higher. There was a lot of noise on the voltage line, but it really was more stable than I expected. While the tantalums were rated for 25V, the power supply is only rated for 18V, so even 18V would be enough to have damaged the circuit. \$\endgroup\$ Commented Jun 5, 2020 at 4:19

2 Answers 2


Tantalums are very sensitive to overvoltage so you have to derate them if you want to use them. They are already typically derated by 30-50% in normal use but you are connect them up directly to a gas engine. Gasoline engines are a very harsh source of power so you should be installing transient suppression and the like anyways such as TVS diodes or MOVs to suppress voltage spikes. Regardless, you probably shouldn't have chosen tantalums in the first place as the input decoupling capacitors knowing they would be directly exposed to something so harsh as a generator.

No LDO, or any type of linear regulator that matter. Having a linear regulator defeats the purpose of having an the efficiency of an SMPS and they are too delicate for the protection task anyways. Furthermore, 18V to 12V with a linear regulator is too much heat for any remotely moderate levels of current.

Get a big TVS diode with a working voltage (not a breakdown voltage) as close to but greater than the battery voltage at full charge. It would help if you could scope to see what the startup transients, and the transients in general are like. There's a chance the TVS diode won't be able to handle the power in which case you need to go with a metal oxide varistor (MOV). But if a TVS diode can do it, then a TVS diode will be better. MOVs do not not clamp as well as TVS diodes and have an inherent wear out mechanism each time they conduct so you don't want to accidentally undersize it if you expect it to be constantly experiencing strikes or else it will wear out early, but they can be made a lot bigger (like bricks!) so can found in much higher power levels.

And go ahead and toss in that 50V aluminum polymer. You probably don't need quite so high as 50V though. Aluminum polymers don't need very much derating.

Might as well toss in a fuse while you're at it.


Tantalum capacitors have a very low effective internal series resistance. A quick, low impedance fed change in voltage from the alternator can cause the current through the tantalum capacitor to exceed its maximum allowed value and blow up the capacitor. I've experienced this behaviour once in a 40 kW IGBT inverter, (repeatedly) blowing out the IGBTs, and the remedy was to insert small series resistances in series in order to limit the equalisation currents to acceptable values. Could it be that you are using an old fashioned alternator with carbon brushes and commutator?

  • \$\begingroup\$ In the case that you don't know what an alternator is, it converts thrust or other forms of energy to electricity. \$\endgroup\$
    – WarpPrime
    Commented Jun 4, 2020 at 14:32
  • \$\begingroup\$ Thanks, that much I was aware of. I was more thinking of car alternators vs generators. In my view an (car) alternator is the old DC generator with carbon brushes carrying the main current, whereas the generator is a AC generator with a diode rectifier where the exciter current is fed through brushes. The brushes in the alternator periodically cut short the wires in the rotor during commutation from one to the other winding. My reasoning was that during this commutation, which is a very low impedance 'event', the tantalium capacitor would be short circuited also, or pulsed, and blow out. \$\endgroup\$
    – HarryH
    Commented Jun 8, 2020 at 16:45
  • \$\begingroup\$ Actually I think now it's just the other way around. The alternator is an AC generator with diode bridge rectifier and the generator is the electrical machine with the commutator. \$\endgroup\$
    – HarryH
    Commented Aug 10, 2020 at 8:45

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