Hello smart people of the internet. Please help me to solve a puzzle. I'm pretty sure there is something simple I'm missing. So here is what I have: I have a 2.2v battery that I want to discharge via R-BAL (see scheme below). I have a MOSFET and a simple switch that controls the gate. There is also a pull-down R2 resistor that keeps the MOSFET closed. Everything works nice here, but the issue that I have is that I want to have my MOSFET to be opened as maximum as possible. To achieve that I need to have Vgs at around 10v.
So, I added a MT3608 DC-DC converter (this one) to my circuit as shown below. Firstly, I do not connect VOUT+ to the gate and measure 10v as shown below. All looks great here.
However, as soon as I connect VOUT+ to the gate, the reading drops back to 2.2v
Here are 2 questions please
- Why does it drop back to 2.2v?
- I suspect the answer to the first question will be something like "you cannot do that because xxx". Therefore my second question is: is it any way for this circuit to have 10v on gate-source of the MOSFET?