# 4N33, optocoupler, photodarlington, getting voltage without connecting any supply

We are using 4N33, optically coupled isolator (datasheet link). The circuit is shown below. In the schematic with R3--> 10K, it was not working so we change to 200K ohm, C2 & ZD1 are not connected. The 4N33 optocoupler is part of the circuit where it is being used for 28V power sensing. The circuit where it is being used has linear voltage regulator of 9V & 5V connected. When the board is being powered ON, we are getting voltage at 3.3V bus, even without connecting 3.3V linear voltage regulator we are getting varying voltage between 0.7V to 2.8V. We are not able to understand even if 28V is not connected, we getting 0.7V to 2.8V in the 3.3V bus. After removing the 4N33 from the IC base, the voltage at 3.3V bus returned to zero.

Then we change the resistor R3 to 6.8M ohm, even with the IC connected the voltage is 0.02V.

Is it EMI noise which is getting amplified. How come without giving 3.3V we are getting voltage. • How exactly are you measuring the voltage? How much can you load it? – CL. Jun 13 at 8:14
• It is measured using multiplier, at node of 3.3V. There is no load connected. – TapasX Jun 13 at 9:12
• Excuse me, but if you say for ex. 5,6V people expect you tell what's the node which has 5,6V when a voltmeter is connected between the ground and that node. You have some different habits. Tell both of the nodes which got the voltmeter between them and use exactly the same terms which are printed in the schematic. Multiplier is not a known measuring equipment. I guess you aimed term multimeter. – user287001 Jun 13 at 10:19
• It's multimeter, connected between 3.3V and ground. – TapasX Jun 13 at 10:44
• Where does the node labeled "15" go? – Andy aka Jun 13 at 12:46