# Find the flux leaving the surface of the sphere: What will the position of line charges look like diagrammatically?

I am not able to understand how the two uniform line charges will look like in space. It would be of great help if someone could draw the uniform line charges in cartesian coordinates and upload it here.

Since I can't give you a 3D image on a 2D screen, let's just take a slice. Luckily the problem is set up to do that reasonably easily. We can represent two at the same, z = +1 and z = -1. The equation for the sphere in A is $$(x-3)^2+(y-1)^2+z^2=2^2$$ for z = +/- 1 $$(x-3)^2+(y-1)^2+1=4$$ $$(x-3)^2+(y-1)^2=3$$ So we can draw a circle with center (3,1) and radius sqrt(3) in the z = +/-1 slice. Since y = 1 is the center, the y = 1, z=+/-1 lines will run right through the center of our slices and the total distance will be the diameter 2*sqrt(3) in both cases for a total distance of $$\ 4 \cdot \sqrt3 \$$ meters. Multiply by 20 for $$\80 \cdot \sqrt3 \$$ nC
Problem B is a little tougher But with a bit of geometry we can show that the chord is 2sqrt(2) for each slice, thus a total charge of $$\ 4 \cdot \sqrt2 \$$ meters or $$\ 80 \cdot \sqrt2 \$$ nC