I've a hard time understanding Thevenin's theorem.
I know that it is just a theorem to simplify a complex circuit, and to easily analyse that. My hard understanding is in the mathematics of it.
Given this circuit, we'd take out the R2, because it is the load resistance, right?(Can you explain me why we need to take it out?)
Also, a load resistence just a load, which is just the main thing of the circuit, that consumes the power, right? Is it the core subject, that the circuit is built for to power?
Now, to get the Vthev, we need to calculate the Rtotal, and here we'd calculate it if it were parallel, but here it is clearly in series, because we took out R2, and and there is no current in that branch anymore, so why we need to calculate it as parallel?
Also, when we need to get the Rthev, why we need to short the voltage sources, and why we don't need the R2?
If I imagine a black box: Does the Rthev basically just the overall resistance of the blackbox between terminal A and B? Therefore this is why we doesn't include the Rload when calculating the Vthev and Rthev?
I don't know if my questions are good, because I'm really confused about it, but can you explain me in simple steps?
In this example the solutions are: VTHEV = 3 V, RTHEV = 60 Ω, INORT = 0.05 A
Rthev = 1/(1/100+1/150): Why we ignore the parallel 200Ohms?
Vthev = (5/250)*150: Again why we ignore the 200Ohms, and here why we calculate the resistance as series and(250Ohms) and not as parallel, like in the case of Rthev(60Ohms)