These value are given:

  • VDD = 15V
  • Zener voltage = 6.8V
  • Zener current = 5mA
  • Rs = 3kOhm

enter image description here here is the link to the data sheet: https://nl.mouser.com/datasheet/2/268/supertex_2n7000-1181251.pdf

I have calculated that R1 most be (15-6.8)/5mA =1.6kOhm but I'm stuck there.

  • \$\begingroup\$ The \$V_{DS}\$ of your M1 should be negliglible so in a first approximation \$V_{A}\$ will be \$V_{RS}\$. \$\endgroup\$
    – po.pe
    Jun 18, 2020 at 5:55
  • \$\begingroup\$ Look up the threshold voltage of the 2N7000. You know the voltage at the gate (6.2 V) so you can determine the voltage across \$R_S\$, you know \$R_S\$ is 3 kohm so you can calculate the current through it. Now check if the 2N7000 needs a large \$V_{GS}\$ to conduct that current, is that \$V_{GS}\$ larger than the threshold voltage? (my guess: it is not but check anyway). You know \$I_D\$ and the voltage across \$R_D\$ + D1, the rest is easy. \$\endgroup\$ Jun 18, 2020 at 8:10

1 Answer 1


Here’s one way to go about solving for the last unknown resistor RD. Because you’re using a MOSFET to create a dc voltage of 10V on drain pin, I’m going make the assumption that the MOSFET will be operating in saturation mode and thus has a drain to source voltage VDS>1V. Now, for it to operate in saturation mode, the gate to source voltage VGS must be greater than the gate threshold voltage VGSth. From your datasheet, this is at minimum 0.8V and Max 3V. Let’s go with 0.8V here as first try. We want VGS>0.8V but also not too large because then we might enter into ohmic region which isn’t what we want. Well let’s see if datasheet can provide more info. If we take a look at the transfer characteristic curve, if we have VGS=2V, we have transistor on, and some current flow. See figure below with marked red lines. This is a start. Now let’s try to find RD. If VGS=2V and VG=6.8V, then VS=4.8V. Then IS= ID =4.8V/3kohm=1.6mA. Now if VA= VD=10V then VRD=15V-0.7V-10V=4.3V. Finally, RD=4.3V/1.6mA=2687 ohm. We can approximate this as 2.7 kohm. If you simulate this circuit with values found, (I have already), you’ll find that VA=10.22V. No bad for first try. If you try again with an adjustment to VGS, you’ll eventually find that RD=2.8kohm will give much better result. enter image description here

enter image description here


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.