The 32VRMS secondary of a transformer feeds a full wave rectifier and capacitor filter as shown in the circuit The peak-to-peak ripple of the output voltage of this circuit needs to be less than 1V when it delivers a current of 3A. A filter capacitor of about 30 000 uF is required. I need to find the frequency.
I am unsure of the formula for finding peak-to-peak ripple voltage of a full wave bridge rectifier.
Is this correct:
V(p-p) = I/(2fC), Therefore, f = 50 Hz.
I am unsure because I have seen the equation : V(p-p) = Vm/(2f R*C) used.
Which equation is correct?