I need to find the root mean square voltage based on this drawing, knowing that the period (T) is equal to 6 seconds, and the voltage (V) is equal to 14 Volt. I know that the rms can be calculated using this formula. How do I apply this into my exercise? rms

enter image description here

knowing that T = 6s, V = 14V find rms voltage.

  • \$\begingroup\$ @muyustan try to stay away from "google that comments" meta.stackexchange.com/questions/15650/… \$\endgroup\$
    – Voltage Spike
    Jun 23, 2020 at 22:58
  • \$\begingroup\$ If this is homework, please provide a solution to the problem as required by site guidelines \$\endgroup\$
    – Voltage Spike
    Jun 23, 2020 at 22:59
  • \$\begingroup\$ @VoltageSpike don't agree, but rules are rules, noted. Your comment in which you tagged med did not bring a notification to me by the way. \$\endgroup\$
    – muyustan
    Jun 24, 2020 at 7:36

2 Answers 2


You have the formula right there, integration is indeed the area under the curve. Over one period, you just have to calculate the area under the voltage waveform/curve squared. It is pretty clear that the time duration between T/4 and T will be 0 even when squared. And you have,

$$V^2 * T/4$$ of area remaining. Inserting V=14 and T=6, $$14*14*6/4 = 294$$ now multiply it with 1/T. $$294*1/6 = 49$$ It is now only a matter of solving the following equation, which I'll leave as an exercise.

$$ V_{rms} = \sqrt{49} $$

  • \$\begingroup\$ Volts not amps unless you meant (A)mplitude. \$\endgroup\$
    – Andy aka
    Jun 24, 2020 at 8:29
  • \$\begingroup\$ @Andyaka Yes I also wanted to write $$V_{rms}$$ but the formula in the question had $$A$$ in left hand side. But you are right that $$A_{rms}$$ does sound like rms current magnitude. It is best to convert A to V. \$\endgroup\$
    – muyustan
    Jun 24, 2020 at 9:08
  • \$\begingroup\$ oh god, how can I write inline mathjax \$\endgroup\$
    – muyustan
    Jun 24, 2020 at 9:09
  • 1
    \$\begingroup\$ @muyustan use \$ instead of $$ \$\endgroup\$
    – JRE
    Jun 24, 2020 at 9:22
  • 1
    \$\begingroup\$ @Andyaka oh my english, could not understand your "tone" exactly, but, I am taking that as a real question, I did not force a linebreak, assumingly, $$lorem ipsum$$ is get printed in a new line automatically. \$\endgroup\$
    – muyustan
    Jun 24, 2020 at 10:50

My solution

I hope that you can read my terrible hand writing.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.