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I need to find the root mean square voltage based on this drawing, knowing that the period (T) is equal to 6 seconds, and the voltage (V) is equal to 14 Volt. I know that the rms can be calculated using this formula. How do I apply this into my exercise? rms

enter image description here

knowing that T = 6s, V = 14V find rms voltage.

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  • \$\begingroup\$ @muyustan try to stay away from "google that comments" meta.stackexchange.com/questions/15650/… \$\endgroup\$
    – Voltage Spike
    Jun 23, 2020 at 22:58
  • \$\begingroup\$ If this is homework, please provide a solution to the problem as required by site guidelines \$\endgroup\$
    – Voltage Spike
    Jun 23, 2020 at 22:59
  • \$\begingroup\$ @VoltageSpike don't agree, but rules are rules, noted. Your comment in which you tagged med did not bring a notification to me by the way. \$\endgroup\$
    – muyustan
    Jun 24, 2020 at 7:36

2 Answers 2

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You have the formula right there, integration is indeed the area under the curve. Over one period, you just have to calculate the area under the voltage waveform/curve squared. It is pretty clear that the time duration between T/4 and T will be 0 even when squared. And you have,

$$V^2 * T/4$$ of area remaining. Inserting V=14 and T=6, $$14*14*6/4 = 294$$ now multiply it with 1/T. $$294*1/6 = 49$$ It is now only a matter of solving the following equation, which I'll leave as an exercise.

$$ V_{rms} = \sqrt{49} $$

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  • \$\begingroup\$ Volts not amps unless you meant (A)mplitude. \$\endgroup\$
    – Andy aka
    Jun 24, 2020 at 8:29
  • \$\begingroup\$ @Andyaka Yes I also wanted to write $$V_{rms}$$ but the formula in the question had $$A$$ in left hand side. But you are right that $$A_{rms}$$ does sound like rms current magnitude. It is best to convert A to V. \$\endgroup\$
    – muyustan
    Jun 24, 2020 at 9:08
  • \$\begingroup\$ oh god, how can I write inline mathjax \$\endgroup\$
    – muyustan
    Jun 24, 2020 at 9:09
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    \$\begingroup\$ @muyustan use \$ instead of $$ \$\endgroup\$
    – JRE
    Jun 24, 2020 at 9:22
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    \$\begingroup\$ @Andyaka oh my english, could not understand your "tone" exactly, but, I am taking that as a real question, I did not force a linebreak, assumingly, $$lorem ipsum$$ is get printed in a new line automatically. \$\endgroup\$
    – muyustan
    Jun 24, 2020 at 10:50
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My solution

I hope that you can read my terrible hand writing.

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