I came across some examples to calculate the current in a circuit with diode and resistance in series. Consider the circuit below:
Current was calculated as follows:
I = (9 - 0.7)/R1
Does that mean that no matter what the resistance R1 is, the voltage drop across it is always 9 - 0.7 Volts? Or in other words, diodes decide the drop across a resistor by varying current through it unlike how in a circuit with only resistors, increasing value of resistance also increased the voltage drop across it?
Also, if the above assumption is true (i.e. taking higher resistance will lower the current value in the circuit but the drop across diode is 0.7v only), but doesn't that violate the V-I graph of a diode where at a specific voltage, a specific current valule should be there while we see different values of current for same value of voltage drop (0.7v)? (based on assumption)