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I have a circuit that looks like the following. It appears to be simple-

enter image description here

What's the thevenin equivalent? I can't seem to simplify it as there are no common nodes that any of the resistors connect.

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    \$\begingroup\$ I would redraw this circuit first to clearly see what is parallel to what \$\endgroup\$ – Eugene Sh. Jun 30 at 17:35
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    \$\begingroup\$ R5 to R1 is as R4 to R2 - redraw to make the image simpler - this always helps. \$\endgroup\$ – Andy aka Jun 30 at 17:44
  • \$\begingroup\$ If you redraw your schematic you will find that it is similar to a "Wheatstone bridge" (not invented by Wheatstone who only popularized another's invention) except that there is a resistor where a source usually is placed. It's a classic case suggesting that you memorize the \$\Delta-Y\$ conversions (both directions may be worth memorizing.) But it can also be solved out using nodal analysis, too. Are you familiar with nodal? \$\endgroup\$ – jonk Jun 30 at 19:32
  • \$\begingroup\$ As others say, you can re-draw this to make it more clear. Also, this problem is often given with further condtions, like R1=R2=R4=R5. If you were given that information, you can simplify the circuit even further with a clever trick. \$\endgroup\$ – The Photon Jun 30 at 20:52
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Use the delta-wye transformation and then you’ll see parallel and series combinations of resistors you can reduce.

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    \$\begingroup\$ Works like a charm- thanks! \$\endgroup\$ – Jaden Ranzenberger Jul 2 at 17:13

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