I was looking at the SN74HC164N shift register datasheet and I noticed something that intrigued me:
There are 2 input signals A and B, but they are NAND'd together to produce the final output. My question is why? I suspect it's so the shift register can have 2 different input sources, though I'm not sure why they would embed that on-chip.
If that's the case and I only have 1 input source, can I just tie the two together and have a 3-wire configuration with