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enter image description here

I've setup a series circuit with an LED and a 1kohm resistor. If I plug the led positive end (longer end) directly to the power positive rail, it lights up.

enter image description here

But if I connect the led positive end to the positive rail with a wire, it does not light up. This looks exactly like the same circuit to me. Nothing has changed other than now there is a wire. What's going on?

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    \$\begingroup\$ "Nothing has changed other than now there is a wire." False, the LED moved. \$\endgroup\$ – Mast Jul 8 at 9:47
  • \$\begingroup\$ Possible duplicate of "How is the breadboard wired internally?" \$\endgroup\$ – Dmitry Grigoryev Jul 9 at 8:21
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The holes in each row are connected together.

Your second circuit has both pins of the LED shorted together.


Just so the photos from grom neer referred to in the comments don't get lost.

Here's the sketch:

enter image description here

The lower sketch shows what happens when you plug an LED into a row of sockets on a breadboard.

This is the schemstic diagram that shows the same thing:

enter image description here

The LED is shown short circuited as will happen if both pins of the LED are plugged into one row on a breadboard.

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  • \$\begingroup\$ By shortening, do you mean this? ibb.co/YNMLfrK image section #2 bottom side. As in, #1 is what I thought was happening. But in fact, it's #2? \$\endgroup\$ – grom neer Jul 7 at 19:43
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    \$\begingroup\$ Not "shortening." "Shorted" an in "short circuited." \$\endgroup\$ – JRE Jul 7 at 19:45
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    \$\begingroup\$ Yes, your drawing is what I meant. \$\endgroup\$ – JRE Jul 7 at 19:46
  • \$\begingroup\$ Okay and one more thing, is this diagram I made an accurate representation of what's going on? ibb.co/55Tbphr. It appears the circuit is still complete and current flows through the resistor. But not in the led/diode component. Because it has been shorted. \$\endgroup\$ – grom neer Jul 7 at 19:52
  • \$\begingroup\$ Yes, the schematic diagram is correct. \$\endgroup\$ – JRE Jul 7 at 19:53
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You're shorting the LED in the second photo. The rows of the breadboard are electrically connected to each of the holes in the same row. Like this:

enter image description here

To add, the two columns on the left and right are connected to each hole in the same column. Like this:

enter image description here

Edit: Pictures are not original, i took them off Google images. Here is the site they originated from: https://computers.tutsplus.com/tutorials/how-to-use-a-breadboard-and-build-a-led-circuit--mac-54746

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  • \$\begingroup\$ By shortening, do you mean this? ibb.co/YNMLfrK image section #2 bottom side. As in, #1 is what I thought was happening. But in fact, it's #2? \$\endgroup\$ – grom neer Jul 7 at 19:34
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    \$\begingroup\$ Are these your own pictures? \$\endgroup\$ – Arsenal Jul 8 at 11:03
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    \$\begingroup\$ Please add links or citations for the images you copied into your answer. We want to make sure that the original creator receives credit for their work. \$\endgroup\$ – Elliot Alderson Jul 8 at 14:24
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    \$\begingroup\$ Done! Sorry, wasn't trying to take credit for what wasn't mine. Just didn't think about it.. \$\endgroup\$ – Michael Jul 8 at 14:37

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