Question is weird but it's about something that I really want to try.

AC power here in India has 50Hz frequency. What I really want to try is to make a series path with two continuous conversions. In start, I want to convert 50Hz AC 230V signal to 100Hz 230V AC signal and at the end of this path I want it to became the same signal of 50Hz AC 230V. That is, I want to convert the frequency of the signal at both ends. At one end multiply it by double and at the other end devide by half. How can I do this?

I tried the cyclo converter circuit but couldn't find the proper result. Is there any modification required in the cyclo converter or any other method available?

  • \$\begingroup\$ If you are looking at a cycloconverter, then you probably aren't looking at "signals." That kind of thing is generally applied to power lines. \$\endgroup\$ – JRE Jul 10 '20 at 13:04
  • \$\begingroup\$ Normally a frequency doubler would work, but they are not meant for raw power, only signals. The parts would be bulky and expensive and waste power. \$\endgroup\$ – user105652 Jul 11 '20 at 4:21

I can give a suggestion. May not work out. It goes something like this, if you don't want to get into complicated complex solution such as AC(50)-DC-AC(100)-DC-AC(150). Please comment if solution seems to be in lines of what you have been implementing.

enter image description here

  • A: 50 Hz signal
  • After passing A signal through a switched converter working to produce something like in Fig. B(Switching at 90 degree to alternate the waveform), you get a 100Hz signal. Now this signal contains many harmonics as n*100Hz.
  • To get the required 100Hz signal, you can pass it through the LPF Filter with cut-off frequency of 100Hz. Getting required 100 Hz signal.

Note: There are many things that needs to be pointed out in this simple looking solution such as:

  • Desired Output 230V may not be the output as there would be attenuation in the circuit

  • Proper 100Hz sine wave may not be there. Since LPF filter are not exactly cut-off at frequency. They have some roll-off rate.

  • Converter might be required to go from A->B. Might complicate the solution

  • Solution seems to be similar to cyclo-converter

  • Filter used may be bulky if used for high-power.

  • \$\begingroup\$ Yes its exectly i want but with the usage of these switched converters as you said harmonics, it will be the problems. suggest if you have more ideas in this or any other. cause i want atleast 90% same output as input (50hz AC) \$\endgroup\$ – Jasmin Temp Jul 10 '20 at 17:26

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.