1
\$\begingroup\$

I am currently designing a MOSFET common source amplifier for my electronics lab class. My issues is that currently I am unable to obtain a gain out of my current circuit design.

I am using a 2N7002 MOSFET in my simulated design My input signal is 1v/100hz with a 12v power supply.

What could be the issue here?

My current desgin Circuit design

Red is my input signal

Green is my output Input and Output

\$\endgroup\$
2
  • 2
    \$\begingroup\$ where are you measuring the output? \$\endgroup\$
    – jsotola
    Commented Jul 17, 2020 at 3:39
  • \$\begingroup\$ How did you derive the biasing conditions? What DC voltage do you see on gate, drain and source? Is that within theFET's linear region? \$\endgroup\$
    – user16324
    Commented Jul 17, 2020 at 9:56

1 Answer 1

1
\$\begingroup\$

With the 2 MΩ and 3.9 MΩ input resistors, the time taken for the bias to set-up correctly on the gate will be approximately the parallel combination of those resistors multiplied by the input capacitance: -

$$\text{(2 MΩ || 3.9 MΩ) x 10 μF} = \text{12.9 seconds}$$

You are only running your simulation for 100 ms so you will never reach the point when the transistor starts to operate correctly. I believe LTSpice can be initialized with the capacitor pre-charged to the appropriate value (7.93 volts). You might want to do that.

Alternatively, try reducing the input capacitor to around 33 nF and watch the MOSFET spring into action a lot quicker.

\$\endgroup\$
2

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.