I've a simple circuit with two parallel resistors, but my derivation of the circuit equations gives a sign the opposite of what I know to occur, so I'm looking for help fixing the error as well as a general strategy for keeping the signs correct in the future. Consider the circuit:
The voltage law on the left gives
$$v=v_1 \Longrightarrow v=i_1 R_1$$
and the circuit law at the top node gives
$$i = i_1 + i_2.$$
Now, I know that the voltage drop across the parallel resisitors should be the same and equal to v. However, when I consider the voltages on the rightmost loop, I see
$$v_1 + v_2 = 0 \Longrightarrow i_1 R_1 + i_2 R_2=0$$
To me, if I have polarity labeled, even if it doesn't matter for resistors, I place positive flow into + as the left and positive flow into - on the right. This is reversed for negative flow. That said, this leads to the incorrect equation above. If we do the outer loop, this gives the correct sign with
$$ v = v_2 \Longrightarrow v = i_2 R_2. $$
which would imply, correctly, that
$$ i_1 R_1 = i_2 R_2. $$
As such, what is the correct sign convention in this case in order to give the correct result? What is a general strategy for determining the sign and maintaining consistency when the current is divided at a node?
