I came across voltage to current (V2I) converter circuit. and I found Iout=Vin/R1. I have a few questions about it:
I believe the op-amp is in the negative configuration because v(3) & v(2) both increase or decrease at the same time to make it negative stable feedback. If Vin increases, temporarily v(3) >v(2), thus output v(1) increases and lets NMOS to conduct more current, having higher I1 current than initial current across it, thus V(R1) increases and hence v(2) increases making it stable.
Intuitive, what is the output voltage of op-amp v(1)? if we have given LF sine wave at Vin? (I believe it'll be sine).
In which region does MOS operate? Is it linear? because we want Current to linearly follow Vgs. What I see is v(1) ~ v(R1) implies Vgs is almost 0, how does MOS even conduct and provide the required Iout=Vin/R1
where phase angle lags by 90 degrees at Higher frequencies, thus creating a possibility of instability(considering non-ideal op-amp also lags the phase), so we add a compensation circuit. How can I add a compensation network? How about attaching a phase lead compensator at v(1)? I think it won't be helpful since gate voltage would decrease in LF operation. But if it is so, how NMOS will allow the Iout amount of current?