1
\$\begingroup\$

I'm currently trying to interface a MIPI camera with my FPGA, a 10M50 on an evaluation board.

The following schematic is taken from the documentation of the board and show how MIPI differential signal is receive by the board and split into 1 High Speed (HS) LVDS and 2 Low power (LP) CMOS signals.

schematic of MIPI Rx port on MAX10 10M50 Evaluation Kit

I'm trying to understand how this montage can separate the two signals and apply level-shifting.

I have found a similar montage in this documentation: AN 754: MIPI D-PHY solution with passive resistor network

From what I understand of MIPI communication, the differential pair switch from LP for control (around 1.2V) and HS to transmit data (around 200mV). The I/O ports of the FPGA are unable to read the HS signal as is, so it need to be shifted to a voltage domain corresponding to the FPGA.

Input range from around 200mV (in HS mode) to 1.2V (in LP mode). On output side, HS is around 1.2V and LP are at 2.5V. see the MIPI receiver part in: MAX10 Evaluation Kit User Guide

Can anyone enlighten me ? Thanks in advance.

\$\endgroup\$
5
  • \$\begingroup\$ Well, the snippet is simple enough and is what it is but you haven't constrained your enquiry as to what voltage levels you are expecting from both outputs. And who knows what are outputs and inputs? \$\endgroup\$
    – Andy aka
    Aug 19 '20 at 15:35
  • \$\begingroup\$ Why doubt it ? Read the spec \$\endgroup\$ Aug 19 '20 at 15:53
  • \$\begingroup\$ I don't doubt it, I need help understanding how it works \$\endgroup\$
    – KilianW
    Aug 19 '20 at 15:58
  • \$\begingroup\$ I could model it for you in Falstad’s web sim. But I have the basics see the eye diagram. (NPI) \$\endgroup\$ Aug 19 '20 at 16:15
  • \$\begingroup\$ I'll take a little time to try to understand your answer, I'll keep you updated. Thanks a lot \$\endgroup\$
    – KilianW
    Aug 19 '20 at 16:23
2
\$\begingroup\$

HS up to 1.5Gbps and LP upto 10Mbps

HS 340mV into 50Ohms per side using CML current source to get +-340mV

LP uses 1.4V driver unipolar reduced to 0, 340mV by impedance divider as a CM signal while not causing HS imbalance of more than =≈5% differential offset.

So LP is a common mode voltage driver at <10M speed and HS is CML differential up to 1.5G all matched impedances.

2 wire analog phones work ≈this way using differential current one way and differential voltage the other thru PHY hybrid XFMR.

Any questions?

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.