I'm new to electronics, but have one straight forward question. I know all boost converters are made up of diodes, caps and coils with some sort of feedback system to regulate voltage.
I bought a 150w boost converter: BMT DC/DC BOOSTER 12-35VOUT 150W
SPECS: Module Properties : Non-isolated Step-up Module (BOOST) Input Voltage : 10-32V Output Voltage : 12-35V (adjustable) Output Current : 6A (max) Input Current : 10A (max) (Please Enhance Heat Dissipation if more than 10A) Output Power : Enhance Heat Dissipation 150W (MAX) Conversion Efficiency: 94% (measured at Input 16V, Output 19V 2.5A) Output Ripple : 2% (max) 20m-Bandwidth Operating Temperature: Industrial (-40 ~ +85°) (ambient temperature exceeds 40°, lower power use, or to enhance heat dissipation) Full load temperature rise: 45° No-load current: 25mA typical Dynamic response speed : 5% 200uS Short Circuit Protection : None (Please Install fuses and protection circuits at Input port.) Input Reverse Polarity Protection : None (Please Series diode at the input port.)
In short it recommends to place a diode (out of interest I've bought a schotkky 10SQ050) in series at the input port to protect against reverse polarity, but what I don't understand is; do I simply just place the diode (with Cathode connected directly to the in+) inline of the In+ line? see figure 1. OR must it be placed in parallel with the in+ and in-? If so then in which direction would the diode be placed? see figure 2
I would really like to understand more. It doesn't make sense to me that the diode is to be placed in series with the input, despite it stating it needs to be in series, so I just want to understand. Please help me understand! Thanks a ton for your time!