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My Deta 1121 carbon monoxide detector is showing no lights. I'd like to test the ceiling socket to determine if the fault is with the wiring or with the detector.

enter image description here

A separate heat detector is on the same RCB circuit and powered on, so I'm hopeful it's just the CO detector that needs replacing.

I have an earlier version of the Silverline 513121 multimeter and believe these are the correct settings to use when testing UK mains electricity: multi meter settings for mains checks

My plan to test if the circuit is live is to:

  1. Set the Multimeter to 600V AC ~
  2. Place the black probe on the Neutral (grey wire) screw
  3. Place the red probe on the Live (brown wire) screw

Could anyone please confirm that sounds sensible?

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    \$\begingroup\$ This isn't an electronics design question. I'll request migration to DIY. \$\endgroup\$
    – Transistor
    Commented Aug 25, 2020 at 10:09
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    \$\begingroup\$ @Whiskeyjack OP mentioned that they are in the UK, so around 240 V would be the correct voltage. \$\endgroup\$ Commented Aug 25, 2020 at 10:57
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    \$\begingroup\$ Sorry guys, I mixed up US and UK. For UK you should expect 220-240 VAC. \$\endgroup\$ Commented Aug 25, 2020 at 11:19
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    \$\begingroup\$ Nicely presented question! Yes, suggested method is good. \$\endgroup\$
    – Russell McMahon
    Commented Aug 25, 2020 at 11:37
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    \$\begingroup\$ I agree, this is a very nicely written question. \$\endgroup\$ Commented Aug 25, 2020 at 11:39

1 Answer 1

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I've just done the test as outlined:

  1. Set the Multimeter to 600V AC ~
  2. Place the black probe on the Neutral (grey wire) screw
  3. Place the rede probe on the Live (brown wire) screw

And got a reading of 243V on the multi-meter. Thanks for the feedback in the comments.

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  • \$\begingroup\$ The irony is after all that the Deta 1121 is now no longer available to buy so I can't just swap in a new one. :) \$\endgroup\$
    – James T
    Commented Aug 25, 2020 at 12:40
  • \$\begingroup\$ Ah! It looks like the BRK CO850MBXi has a compatible base. \$\endgroup\$
    – James T
    Commented Aug 25, 2020 at 15:14

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