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I'm asked to find IB, IC and VCE. ode

This is my answer:

my answer is true are not ,VCE Value is nagative is it true are not

I wonder if my answer is true are not. VCE Value is negative, is this true or not?

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  • \$\begingroup\$ Apply KVL properly for calculating base current. \$\endgroup\$
    – Sadat Rafi
    Commented Aug 27, 2020 at 14:02
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    \$\begingroup\$ Already the first formula is incomplete. A relatively large value was left out. \$\endgroup\$
    – csabahu
    Commented Aug 27, 2020 at 14:13
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    \$\begingroup\$ @MuhammadNaeem this is a discussion site. Plus my comment directly indicates that your answer should be incorrect. \$\endgroup\$
    – Sadat Rafi
    Commented Aug 27, 2020 at 14:47
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    \$\begingroup\$ @Sadat, "this is a discussion site". No, it's a question and answer site. It's quite specifically not for discussion (even though that's what I'm doing here). Hmmm. \$\endgroup\$
    – Transistor
    Commented Aug 27, 2020 at 15:04
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    \$\begingroup\$ Can someone please acknowledge that the OP actually showed his own attempt at a solution, rather than simply posting the question and saying "What is the answer?" +1 for showing your own work, even if it is incorrect. Well done! \$\endgroup\$
    – DerStrom8
    Commented Aug 27, 2020 at 15:21

3 Answers 3

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If I read your notes correctly out of 12V supply you got Vce of about 21KV? Looking at Ib assuming you get about 1mA and you multiply by beta of 100 therfore you get 100mA not 100A.Please check how you calculated Ib again.

To answer your question Vce in this circuit cannot be negative with 12V supply at collector and ground at emitter resistor.

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answer part A[![thankyou i am done][2]][2]

thanyou

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part 2 answer

answer part 2 thanyou i am done

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    \$\begingroup\$ “answer part 2 thanyou i am done”? This is not very polite way to ask someone for help. Users of this forum help others out of their own good will. Therefore, attitude that they own you answer is wrong. I can help you with hints and ideas but it is your home/course work. So, please be polite and ask specific question. \$\endgroup\$
    – Wintermute
    Commented Aug 28, 2020 at 10:19

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