Did I interpret these multisim results correctly?

Question

From the circuit above, this is what I have to do: " Connect the circuit with R3 equal to 470 kΩ. Set the input frequency to 100 Hz. Adjust the signal level to get an output of 5 Vp-p. Record gain and upper cut off frequency. Multiply gain and bandwidth."

What I did was this:

I used a function generator and made the frequency to 100Hz. As for amplitude, I chose 1.25 Vp so that in PR1 it shows 5vp-p (I drew a red arrow and labelled it as 1 to make it easier to locate). This is what it meant by "Adjust the signal level to get an output of 5Vp-p" right?

Next, in order to get the gain. I placed a probe (PR2) at the output and made PR1 as the reference. Then in the list of values, there's a V(gain_AC) which is equal to 5.66 (Again, I drew a red arrow and labelled it as 2). Is this the gain of the circuit already?

Lastly, to get the cut off frequency I did an ac sweep and located where it drops by 3db (I already changed the vertical scale to decibels). The result is the following:

Is the value that I highlighted which is 2.1348k the upper cut-off frequency I'm looking for? And, this is also the bandwidth right?

To sum it up, I basically have three questions:

1. Was I able to adjust the signal level properly to get an output of 5 Vp-p?
2. Is the V(gain_AC) shown by the probe, the actual gain of the circuit?
3. In the AC sweep I did, is the value I highlighted the upper cut-off frequency and the bandwidth?

If you need more information, please tell me. Thank you so much for your help!

Answer 1

Was I able to adjust the signal level properly to get an output of 5 Vp-p?

No.
You have probed circuit output properly. It shows a voltage amplitude of 28.2V peak-to-peak. However, this measurement is not to be trusted. Had you actually looked at the waveform, it would not be sinusoidal. It would look more like a square wave: when you apply a sine wave at amplifier input, you should see a sinusoidal wave shape at amplifier output.
A too-large input signal asks of the amplifier to generate an output amplitude that exceeds its DC supply voltages. Since your DC supply range is 30V, that 28.2V p-p output signal is limited to a little less than this range (output can only approach, not exceed DC supply).

Is the V(gain_AC) shown by the probe, the actual gain of the circuit?

No
As stated above, a sine wave applied should yield a sinusoidal wave at amplifier output. This amplifier is driven with an input amplitude that is too high. A lower input amplitude should be set on the function generator. Set it low enough so that output amplitude eventually drops to 5V p-p.
As a check, if you reduce input amplitude in half, output amplitude should also reduce by half - this check indicates that the amplifier is running linearly.

In the AC sweep I did, is the value I highlighted the upper cut-off frequency and the bandwidth?

Your method seems correct. Once you get the amplifier running linearly, do this again - you'll likely get a different result.