# Circuit of a potentiometer with switch

in a device I have bought there is this potentiometer with switch:

It has 5 pins instead of 3 as a normal potentiometer: two of them are connected to VCC and GND, the other ones i do not know (there is not a schematic of that device).

Do you know the equivalent circuit of this potentiometer with switch? I need for it because I want to measure the voltage across one portion of the potentiometer while tuning it.

The switch and the potentiometer are completely independant. the 2-pin connector is for the switch and the 3-pin for the potentiometer. VCC and ground are connected to the lateral pins of the pentiometer the middle one is the output variable voltage.

• Thank you for your answer. Now I have this doubt: if the switch is closed, will GND and VCC be shorted and the potentiometer will be bypassed? How is this possible? Sep 24, 2020 at 10:41
• the swicth is not connected to the potentiometer unless you connect it. It is on the 2-pin connector. the potentiometer is on the 3-pin connector Sep 24, 2020 at 10:43

simulate this circuit – Schematic created using CircuitLab

Figure 1. This is what you've got.

It has 5 pins instead of 3 as a normal potentiometer:

Look into it. It should be very clear that there are two independent layers or wafers.

... two of them are connected to VCC and GND,

Make sure you don't connect the switch wires to VCC and GND. If you do you will short-circuit the supply and possibly damage the switch.

... the other ones i do not know (there is not a schematic of that device).

You should be able to figure it out with the above diagram and a resistance meter.

Do you know the equivalent circuit of this potentiometer with switch?

You've got it.

I need for it because I want to measure the voltage across one portion of the potentiometer while tuning it.

Measure between any two terminals while rotating the shaft.