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Is it possible in a circuit that a capacitor has uneven charges on its plates? I mean Q1 is not equal to -Q2 in a certain instant of time.

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    \$\begingroup\$ Yes, at very high frequencies where the wavelength of the signal is getting to within a ball-park of the distances involved. \$\endgroup\$
    – Andy aka
    Commented Oct 23, 2020 at 14:22
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    \$\begingroup\$ Basically, yes on a timescale close to the speed of light. Pump charge in one side, its electric field has to propagate at the speed of light through the dielectric, which reduces as 1/sqrt(dielectric constant). \$\endgroup\$
    – user16324
    Commented Oct 23, 2020 at 14:48
  • \$\begingroup\$ Thanks for the answers! How can I close this topic? \$\endgroup\$ Commented Oct 23, 2020 at 16:22

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From the comnents of Andy aka and Brian Drummond: Yes, when the signal's wavelength has same or smaller magnitude as the physical size of the capacitor.

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