1
\$\begingroup\$

enter image description here

I just started learning about source transformation and came across this question. I get that I can replace the current sources with voltage sources in series along with the resistors in series as well. But what do I do about the the voltage dependant voltage source and resistor in parallel at the middle of the circuit? Turning the vdvs to current source wont help me since the resistor would still be in parallel. What am I missing?

\$\endgroup\$
3
  • \$\begingroup\$ are you certain that it is a voltage dependant voltage source? \$\endgroup\$
    – jsotola
    Oct 29, 2020 at 17:22
  • \$\begingroup\$ It's current dependent current source \$\endgroup\$
    – Andy aka
    Oct 29, 2020 at 17:42
  • \$\begingroup\$ slideplayer.com/slide/6880670/23/images/82/… \$\endgroup\$
    – Andy aka
    Oct 29, 2020 at 18:09

1 Answer 1

2
\$\begingroup\$

It seems to be a current dependent current source. If it's true you can replace it with a (11/2,3) Ohm resistor and the problem contains a kind of fool's trick.

It still needs some work to be solved after the replacement.

Assuming it's a voltage source with formula U=2,3Ix leads to a contradiction.

\$\endgroup\$
2
  • \$\begingroup\$ You mean 11/3,3 \$\endgroup\$ Oct 29, 2020 at 17:37
  • 1
    \$\begingroup\$ No, the current source should be replaced with (11/2,3) Ohms. Then there's still the 11 Ohm. I didn't claim anything about it. It stays or will be in the future combined with the (11/2,3 ) Ohm resistor. \$\endgroup\$
    – user136077
    Oct 29, 2020 at 17:43

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.