In a CAN network, the ends of the network has to be terminated with 120 ohm - I understand this. The middle node in the below diagram is the stub node and it does not have to be terminated, my stub CAN node design has high ohmic 9280 ohm resistor. Any idea why 9280 ohm(Two 4.64k in series) is chosen, what is the idea behind this.
I came across another app note about stub node termination where they have used two 1.3k ohm resistors, but in my stub CAN node, two 4.64k resistors are used. Any idea why 4.64k resistors are used. I referred many application notes but did not find anything regarding two 4.64k resistor termination network.