0
\$\begingroup\$

I was trying to analyse an ideal transformer with one ideal independent voltage source on each winding.

I got a relationship between those voltage sources but it contradicts the fact that both voltage sources are independent of each other and there should not be any such relationship between them.

Here is my solution:

enter image description here

enter image description here

What is the reason behind this contradiction?

\$\endgroup\$
6
  • 7
    \$\begingroup\$ You can't make such a circuit out of ideal components. It is not physical. You have two ideal entities forcing different voltages on the same point. \$\endgroup\$
    – Eugene Sh.
    Commented Nov 13, 2020 at 15:11
  • \$\begingroup\$ If both voltage sources are the same value, frequency and phase then you can do it (for N=1). I don't see how you got the turns ratio to be negative though \$\endgroup\$
    – Andy aka
    Commented Nov 13, 2020 at 15:20
  • 1
    \$\begingroup\$ The reason ideal components are ideal and cannot exist in reality is because a a contradiction can always be found somewhere when using them. If you find a contradiction with ideal components, it doesn't mean that there is something wrong with your work. \$\endgroup\$
    – DKNguyen
    Commented Nov 13, 2020 at 15:52
  • \$\begingroup\$ You can find contradiction if you apply Kirchoff's law after you put an ideal 5V battery across an Ideal 10V battery as well. Or if you put a zero ohm resistor across a voltage source and calculate the voltage across the resistor using ohm's law. Lesson: Never linger too much on "Ideality". Let's think real. \$\endgroup\$
    – Mitu Raj
    Commented Nov 13, 2020 at 17:19
  • \$\begingroup\$ What is M? what does MdI_1/dt accoutn for? \$\endgroup\$
    – Brian
    Commented Mar 6, 2021 at 22:28

3 Answers 3

5
\$\begingroup\$

A shorter version of this would be to replace an ideal 1:1 transformer with wires.

The result is the same: two independent sources in a fight.

An ideal transformer with a coupling constant of unity just reflects the voltage on one port to a scaled version on the other, at the same time that it reflects current. Because it is infinitely stiff in this regard, if you excite it with an ideal voltage source, you have to treat the other side as an ideal voltage source.

Ditto, if you excite one side with an ideal current source, you must treat the other side as an ideal current source.

When you use ideal components, you need to observe some rules to avoid conflicts like this (or you need to accept infinite currents and/or voltages). That's just how it is.

\$\endgroup\$
2
  • \$\begingroup\$ ‘Short’er - I see what you did there :-) \$\endgroup\$
    – Frog
    Commented Apr 2, 2023 at 7:59
  • \$\begingroup\$ @Frog: I didn't! That's a good one. \$\endgroup\$
    – TimWescott
    Commented Apr 2, 2023 at 17:46
1
\$\begingroup\$

To better understand the transformer behavior, insert 0.1 ohms in the left side, in series with the ideal voltage source.

And replace the right side source with a 100 ohm resistor.

Now vary that 100 ohms, and observe the current from the left side source, and observe the voltage across that 0.1 ohm resistor.

\$\endgroup\$
0
\$\begingroup\$

You can use superposition concept to solve this. Turn off one side of the voltage source and replace it with a short circuit. Then you will need infinite current. Therefore, this is impossible in real life.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.