1
\$\begingroup\$

I was asked to implement a logic expression (F = A'B' + C'D' + AC') with AND-OR-INVERT(AOI) gates. I made the circuit (Figure 1) below, but I looked it up on Wikipedia and found that AOI gates are made out of two AND gates and a single NOR gate. So I made the second circuit (Figure 2), but their outputs were different eventhough their inputs were the same. I would really appreciate it if someone could explain this to me, thanks.

Figure 1

enter image description here

Figure 2

enter image description here

\$\endgroup\$
4
  • \$\begingroup\$ Are you only allowed to use and-or-invert gates? Or are other gates permitted? \$\endgroup\$
    – jonk
    Nov 15, 2020 at 6:55
  • \$\begingroup\$ Yes, but im not sure if and-or-inverter means and, or, not gates or and, nor gates. \$\endgroup\$
    – Kalamakra
    Nov 15, 2020 at 9:07
  • \$\begingroup\$ Well, if you put the same input value into all four inputs then the output will be the inverted input value. I'm curious what you are allowed. That's not clear to me, yet. \$\endgroup\$
    – jonk
    Nov 15, 2020 at 9:10
  • \$\begingroup\$ We are only allowed to use AND-OR-INVERT gates. \$\endgroup\$
    – Kalamakra
    Nov 15, 2020 at 10:51

1 Answer 1

Reset to default
1
\$\begingroup\$

Your first gate realization does indeed implement \$F =A'B' +C'D' + AC' \$

As far as I can see, your second circuit implements \$F =(AB +CD)' + AC' =(AB)'(CD)'+AC'\$

Those two expressions are not equivalent, hence why you get different outputs from the same inputs.

\$\endgroup\$
2
  • \$\begingroup\$ Yes thats why I'm getting different outputs, but is my first circuit a and-or-invert circuit? \$\endgroup\$
    – Kalamakra
    Nov 15, 2020 at 9:08
  • \$\begingroup\$ Yes, your first circuit only utilizes AND-gates, OR-gates and inverters. A so-called AND-OR-Invert realization. \$\endgroup\$
    – Carl
    Nov 15, 2020 at 9:11

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.