I have a question concerning the capacitive coupling between two conductors. The capacitance C between the two is only a function of the diameter of the 2 studied conductors, the insulation thickness of the latter and distance between the two. My question is, since the charge on each conductor is equal to |Q| =|C*V| where V is the potential difference between the two conductors, the charge distribution should remain the same as long as V=1, right?

  • \$\begingroup\$ ... And capacitance remains the same. \$\endgroup\$ – Andy aka Nov 19 '20 at 16:06
  • \$\begingroup\$ The capacitance is the same no matter the voltage distribution, it characterizes the coupling between the two conductors. I asked the question because when running a FE simulation, the charge varies with the voltage (even though the difference of potential remains =1) \$\endgroup\$ – Wallflower Nov 19 '20 at 16:08
  • \$\begingroup\$ Is there a ground anywhere other than infinity? \$\endgroup\$ – Neil_UK Nov 19 '20 at 16:23
  • \$\begingroup\$ only infinity considered as the ground for this case study \$\endgroup\$ – Wallflower Nov 19 '20 at 16:30
  • 1
    \$\begingroup\$ Don't conflate total charge with charge distribution. They are not the same thing. \$\endgroup\$ – Elliot Alderson Nov 19 '20 at 19:07

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